Partition by a threshold in Java
Java interview exercise on Streams & lambdas, difficulty 2 of 3. Solve it in the editor beside a worked example; the tests run the moment you do.
Write partition(nums, threshold) that returns a Map<Boolean, List<Integer>> with the numbers at or above the threshold under true and the rest under false, in their original order. Collectors.partitioningBy always produces both keys, even when one list is empty.
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